Completing the square metods i want to unerstand
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{tex}x^2 +\xa06x – 16 = 0{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}x^2 + 6x = 16{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}x^2 + 6x + 9 = 16 + 9{/tex} [Adding on both sides square of coefficient of x, i.e. ({tex}\\frac{6}{2}{/tex})2]{tex}\\Rightarrow{/tex}\xa0{tex}(x + 3)^2 = 25{/tex}{tex}\\Rightarrow{/tex}\xa0x + 3 =\xa0{tex}\\pm{/tex}{tex}\\sqrt{25}{/tex}{tex}\\Rightarrow{/tex}\xa0x + 3 =5 or x + 3 = -5{tex}\\Rightarrow{/tex}\xa0x = 2 or x = -8