चित्र में प्रदर्शित ट्रांजिस्टर के CE निर्गत अभिलाक्षणिक से ट्रांजिस्टर के `beta _(ac )` का परिकलन कीजिये।
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`beta_(ac)=((Delta I_(C))/(Delta I_(B)))_(V_(CE))`
चित्र में, `V_(CE)=10` वोल्ट पर, बिन्दु A व B के बीच
`Delta I_(C)=10-5=5 mA`
`Delta I_(B)=100-50=50mu A=0.050 mA`
`therefore beta_(ac)=(5)/(0.050)=100`