CH3MgI will give methane with
(A) C2H5OH
(B) CH3–CH2–NH2
(C) both of these (A and B)
(D) None of these
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Correct option (C) both of these (A and B)
Explanation:
Grignard’s reagent reacts with primary or secondary amines to give alkanes but fail to react with tertiary amines due to lack of hydrogen on nitrogen.
R-MgX + R-NH₂ → R-H + Mg(NHR)
The reaction between ethanol and Grignard is shown below:
CH3CH2OH + R’MgX → CH3CH2O-(MgX)+ + R’-H