An aqueous solution contain `Hg^(2+),Hg_(2)^(2+),Pb^(2+)`.THe addition of `2M HCI` will procipitate.
A. `HgCI_(2)`only
B. `PbCI_(2)”only”^(-)`
C. `PbCI_(2)` and `Hg_(3)CI_(2)`
D. `PbCI_(2)` and `CdCI_(2)`
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Correct Answer – a
Both `Bi^(3+) and Cd^(2+)` will be precipitate in `Bi_(2)S_(3)` (black) and `CdS` (yellow) by `H_(2)S` as both low values of `K_(sp)` than `AI^(3+),Zn^(2+) and Ni^(2+)` (as sulphides)
Correct Answer – b
`Fe^(3+) + 3NH_(4)OH rarr Fe(OH)_(3) darr (“reddish brown”) +3NH_(4)^(o+)`
`Cu^(2+) + 4NH_(3) rarr underset((“blue colour soluble complex”))([Cu(NH_(3))_(4)]^(2+))`
` Zn^(2+) + 4NH_(3) rarr underset((“colourless soluble complex”))([Zn(NH_(3))_(4)]^(2+))`
Correct Answer – c
`2M MCI` is group reagent for reagent for group 1 cation `PbCI_(2)` And `HgCI_(2)` will get precipitated, is their solubility products `(K_(sp))` are less than that of other radical