Car accelerates from 18km/h to 36km/h in 5 sec find acceleration and distance travelled
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Dis=ut+at*t But time is in sec. Then we convert km to meter= u=1 m/s and v=2 m/s (by multiplying them by 5/18)=1*5+9*5*5=5+225=230mSo, distance is 230meter
Acc.=v-u/2=(36-18)/2=9So, acc.=9 km/sec square