Calculate the wavelength of the spectral line obtained in the spectrum of `Li^(2+)` ion when the transition takes place between two levels whose sum is 4 and the difference is 2
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Suppose the transition takes place between levels `n_(1) and n_(2)`
Then `n_(1) + n_(2) = 4 and n_(2) – n_(1) = 2`
Solving these equations, we get `n_(1) = 1, n_(2) = 3 :. (1)/(lamda) = R ((1)/(n_(1)^(2)) – (1)/(n_(2)^(2))) Z^(2)`
For `Li^(2+) , Z = 3 :. (1)/(lamda) = 109, 677 cm^(-1) ((1)/(1^(2)) – (1)/(3^(2))) xx 3^(2) = 109, 677 xx ((1)/(1) – (1)/(9)) xx 9 cm^(-1) = 109677 xx 8 cm^(-1)`
or `lamda = (1)/(109677 xx 8 cm^(-1)) = 1.14 xx 10^(-6) cm`