`q = n xx C xx DeltaT = ((60)/( 27) mol) ( 24 J mol^(-1) K^(-1)) ( 55 – 35K) =1066 .7 J =1.07 kJ `
Calculate the number of `KJ` necessary to raise the temperature of `60.0 gm` of aluminium from `35^(@)` to `55^(@)C`. Molar heat capcacity of `Al` is `24 J mol^(-1)K^(-1)`
Mustafa Deshpande
Asked: 3 years ago2022-11-01T22:25:13+05:30
2022-11-01T22:25:13+05:30In: General Awareness
Calculate the number of kJ necessary to raise the temperature of `60.0` g of aluminium from 35 to `55^(@)C` . Molar heat capacity of aluminium is`24J mol^(-1)K^(-1)`.
Calculate the number of kJ necessary to raise the temperature of `60.0` g of aluminium from 35 to `55^(@)C` . Molar heat capacity of aluminium is`24J mol^(-1)K^(-1)`.
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Gulzar Rao Tara
Asked: 3 years ago2022-10-29T12:33:13+05:30
2022-10-29T12:33:13+05:30In: General Awareness
Calculate the number of kJ necessary to raise the temperature of 60 g of aluminium from 35° C to 55 °C. Molar heat capacity of Al is 24 J /mol/ K
Calculate the number of kJ necessary to raise the temperature of 60 g of aluminium from 35° C to 55 °C. Molar heat capacity of Al is 24 J /mol/ K
Leave an answer
Leave an answer
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Energy required q = Cm x n x Δ T
= 24(J/mol/K) X 2.22(mol) X 20 (K )
[Δ T = 55°C-35°C =20 °C=20 K]
= 1066.8 J
or 1.07 KJ
`q = nC Delta T = ((60)/(27)) xx 24 xx (55-35) = 1066 J = 1.066 kJ`