Calculate the Gibbs energy change for the reaction given below:
`Zn_((s))+Cu_((s))^(2+)toCu_((s))+Zn_((aq.))^(2+)`
Given that standard Gibbs energy (`G^@`) for `Zn_((aq.))^(2+),Cu_((aq.))^(2+)` are `-147.2 kJ mol^(-1)` and `65.0 kJ mol^(-1)` respectively.
`Zn_((s))+Cu_((s))^(2+)toCu_((s))+Zn_((aq.))^(2+)`
Given that standard Gibbs energy (`G^@`) for `Zn_((aq.))^(2+),Cu_((aq.))^(2+)` are `-147.2 kJ mol^(-1)` and `65.0 kJ mol^(-1)` respectively.
`DeltaG^(@)=SigmaG_(“products”)^(@)-SigmaG_(“reaction”)^(@)`
`=[0+(-147.2)-(0+65.0)]`
`=-212.2 kJ`