Calculate the entropy change `(J//mol K)` of the given reaction. The molar entropies `(J//K-mol)` are given in brackets after each substance:
`2PbS(s)[19.2]+3O_(2)(g)[205.1]`
` to 2PbO(s)[66.5]+2O_(2)(g)[248.2]`
A. `-113.5`
B. `-168.3`
C. `+72.5`
D. `-149.2`
`2PbS(s)[19.2]+3O_(2)(g)[205.1]`
` to 2PbO(s)[66.5]+2O_(2)(g)[248.2]`
A. `-113.5`
B. `-168.3`
C. `+72.5`
D. `-149.2`
Correct Answer – B
`Delta_(r )S=(2xx248.2)+(2xx66.5)`
`-(2xx91.2)-3(205.1)`
=-168.3 J