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Nishita Faisal Barad
Asked: 2022-11-09T16:14:59+05:30 In:

Calculate the enthalpy of vaporisation per mole for ethanol. Given `DeltaS = 109.8 J K^(-1) mol^(-1)` and boiling point of ethanol is `78.5^(@)`.

Calculate the enthalpy of vaporisation per mole for ethanol. Given `DeltaS = 109.8 J K^(-1) mol^(-1)` and boiling point of ethanol is `78.5^(@)`.
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  1. The entropy change for vaporisation,
    `Delta_(vap)S^(Theta) = (Delta_(vap)H)/(T_(b))`
    or `Delta_(vap)H^(Theta) = Delta_(vap)S^(Theta)T_(b)`
    `DeltaS^(Theta) = 109.8 J K^(-1)mol^(-1), T_(b) = 273 +78.5 = 351.5K`
    `:. DeltaH^(Theta) = (109.8 xx 351.5) = 38.595 kJ mol^(-1)`

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