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Anusha Binnani
Asked: 2022-11-04T07:01:32+05:30 In:

Calculate the amount of water (g) produced by the combustion of 16 g of methane

Calculate the amount of water (g) produced by the combustion of 16 g of methane
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  1. The balanced equation for the combustion of methane is :
    `CH_(4) (g) +2O (g) to CO_(2) (g) +2H_(2) O(g) `
    (i) 16 g of `CH_(4) ` corresponds to one mole
    (ii) From the above equation .1 mol of
    `CH_(4) (g) ` gives 2 mol of `H_(2) O` (g)
    2 mol of water `(H_(2)O) =2xx(2+16) `
    ` =2xx18=36 g`
    1 mol `H_(2) O =18 g H_(2)O implies (18g H_(2)O)/(1 mol H_(2) O)`
    `=2xx18 g H_(2)O=36 g H_(2)O`

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Atul Ram Sachdev
Asked: 2022-10-30T22:01:05+05:30 In:

Calculate the amount of water (g) produced by the combustion of 16g of methane

Calculate the amount of water (g) produced by the combustion of 16g of methane
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  1. 20 gm water is produced

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Rajesh Dhanush Bahri
Asked: 2022-10-29T06:32:10+05:30 In:

Calculate the amount of water g produced by the combustion of 16g of methane

Calculate the amount of water g produced by the combustion of 16g of methane
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  1. According to the above equation, one mole of CH4 (16 g) on combustion gives one mole of carbon dioxide and 2 moles of water and 2 moles of water = 2 x [2 + 16] = 36 g of water.

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