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Aayushman Wali
Asked: 2022-11-05T06:58:16+05:30 In:

Calculate `Delta_(f)H^(@)` (in kJ/mol) for `Cr_(2)O_(3)` from the `Delta_(r)G^(@)` and the `S^(@)` values provided at `27^(@)`
`4Cr(s)+3O_(2)(g)rarr2Cr_(2)O_(3)(s),” “Delta_(r)G^(@)=-2093.4kJ//mol`
`S^(@)(“J//K mol”) : S^(@)(Cr,s)=24,” “S^(@)(O_(2),g)=205,” “S^(@)(Cr_(2)O_(3),s)=81`
A. `-2258.1 kJ//mol`
B. `-1129.05 kJ//mol`
C. `-964.35 kJ//mol`
D. `3462kJ//mol`

Calculate `Delta_(f)H^(@)` (in kJ/mol) for `Cr_(2)O_(3)` from the `Delta_(r)G^(@)` and the `S^(@)` values provided at `27^(@)`
`4Cr(s)+3O_(2)(g)rarr2Cr_(2)O_(3)(s),” “Delta_(r)G^(@)=-2093.4kJ//mol`
`S^(@)(“J//K mol”) : S^(@)(Cr,s)=24,” “S^(@)(O_(2),g)=205,” “S^(@)(Cr_(2)O_(3),s)=81`
A. `-2258.1 kJ//mol`
B. `-1129.05 kJ//mol`
C. `-964.35 kJ//mol`
D. `3462kJ//mol`
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  1. Correct Answer – B
    `Delta_(r)G^(@) = Delta_(r)H^(@)-T xx Delta_(r)S^(@)`
    `Delta_(r)S^(@) = 2 xx 81 -4xx 24 -3 xx 205 J//mol`
    `:. Delta_(r)H^(@) = -2258.1 kJ//mol`
    `Delta_(r)H^(@) = 2 xx Delta_(f)H^(@)(Cr_(2)O_(3), s)`
    `:. Delta_(f)H^(@)(Cr_(2)O_(3), s) = -(2258.1)/(2)`
    `= -1129.05 kJ//mol`.

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Aabha Eddie Usman
Asked: 2022-10-31T23:21:17+05:30 In:

Calculate `Delta_(f)H^(@)` (in kJ/mol) for `Cr_(2)O_(3)` from the `Delta_(r)G^(@)` and the `S^(@)` values provided at `27^(@)`
`4Cr(s)+3O_(2)(g)rarr2Cr_(2)O_(3)(s),” “Delta_(r)G^(@)=-2093.4kJ//mol`
`S^(@)(“J//K mol”) : S^(@)(Cr,s)=24,” “S^(@)(O_(2),g)=205,” “S^(@)(Cr_(2)O_(3),s)=81`
A. `-2258.1kJ//mol`
B. `-1129.05kJ//mol`
C. `-964.35kJ//mol`
D. None of these

Calculate `Delta_(f)H^(@)` (in kJ/mol) for `Cr_(2)O_(3)` from the `Delta_(r)G^(@)` and the `S^(@)` values provided at `27^(@)`
`4Cr(s)+3O_(2)(g)rarr2Cr_(2)O_(3)(s),” “Delta_(r)G^(@)=-2093.4kJ//mol`
`S^(@)(“J//K mol”) : S^(@)(Cr,s)=24,” “S^(@)(O_(2),g)=205,” “S^(@)(Cr_(2)O_(3),s)=81`
A. `-2258.1kJ//mol`
B. `-1129.05kJ//mol`
C. `-964.35kJ//mol`
D. None of these
Parabola
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1 Answer

  1. Correct Answer – B
    `Delta_(r)G^(@)=Delta_(r)H^(@)-TxxDelta_(r)S^(@)`
    `Delta_(r)S^(@)=2xx81-4xx24-3xx205J//mol`
    `therefore” “Delta_(r)H^(@)=-2258.1 kJ//mol`
    `Delta_(r)H^(@)=2xxDelta_(f)H^(@)(Cr_(2)O_(3),s)`
    `thereforeDelta_(f)H^(@)(Cr_(2)O_(3),s)=-(2258.1)/(2)`
    `=-1129.05″kJ/mol”`

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