By what % will the illumination of the lamp decrease if the current drops by 20% ?
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\xa0H = I^2Rtif the current drops by 20%so, new current (I\’) = 0.8I\xa0Hence, H\’ = (0.8I)^2RtH\’ = 0.64HHence, the brightness would decrease by H-(0.64H)/100 = 36%