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Arjun Nori
Asked: 2022-11-10T03:19:50+05:30 In:

Both the strings, shown in figure, are made of same material and have same cross-section. The pulleys are light. The wave speed of transverse wave in the string `AB` is `v_(1)` and in `CD` it is `v_(2)`, the `v_(1)//v_(2)` is
image
A. `1`
B. `2`
C. `sqrt(2)`
D. `(1)/(sqrt(2))`

Both the strings, shown in figure, are made of same material and have same cross-section. The pulleys are light. The wave speed of transverse wave in the string `AB` is `v_(1)` and in `CD` it is `v_(2)`, the `v_(1)//v_(2)` is
image
A. `1`
B. `2`
C. `sqrt(2)`
D. `(1)/(sqrt(2))`
Parabola
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  1. Correct Answer – C
    `V prop sqrt(1)`
    `(V_(1))/(V_(2)) = sqrt((T_(1))/(T_(2))) = sqrt((2T)/(T)) = sqrt(2)`

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Chitranjan Raghavan
Asked: 2022-11-07T23:43:48+05:30 In:

both the strings , shown in figure are made of same material and have same cross – section. The pulleys are light the wave speed pf a travsverse wave in the string AB is `v_(1)` and in CD is `v_(2)`. The ratio `v_(1) // v_(2)` is
image
A. 1
B. 2
C. `sqrt2`
D. `1sqrt2`

both the strings , shown in figure are made of same material and have same cross – section. The pulleys are light the wave speed pf a travsverse wave in the string AB is `v_(1)` and in CD is `v_(2)`. The ratio `v_(1) // v_(2)` is
image
A. 1
B. 2
C. `sqrt2`
D. `1sqrt2`
Parabola
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Leave an answer

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1 Answer

  1. Correct Answer – D

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