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Rita Oak
Asked: 2022-11-06T05:11:54+05:30 In:

Binding energy per nucleus of `._(1)^(2)H` and `._(2)^(4)He` are 1.1 MeV and 7 MeV respectively. Calculate the amount of energy released in the following process:
`._(1)^(2)H + ._(1)^(2)H to ._(2)^(4)He`

Binding energy per nucleus of `._(1)^(2)H` and `._(2)^(4)He` are 1.1 MeV and 7 MeV respectively. Calculate the amount of energy released in the following process:
`._(1)^(2)H + ._(1)^(2)H to ._(2)^(4)He`
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  1. Amount of energy released
    `= sum` Binding energy of products
    `- sum` Binding energy of reactions
    `=[4 xx 7] – [4 xx 1.1] = 23.6 MeV`

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