At `27^@C` latent heat of `I^-` fusion of a compound is `2.7xx10^3 J mol^(-1)`. Calculate the entropy change during fusion.
A. `9.77 JK^(-1) “mol”^(-1)`
B. `10.73 JK^(-1)”mol”^(-1)`
C. `2930 JK^(-1)”mol”^(-1)`
D. `108.5 JK^(-1)”mol”^(-1)`
A. `9.77 JK^(-1) “mol”^(-1)`
B. `10.73 JK^(-1)”mol”^(-1)`
C. `2930 JK^(-1)”mol”^(-1)`
D. `108.5 JK^(-1)”mol”^(-1)`
Correct Answer – A
Entropy , `DeltaS_(f) =(DeltaH_(f))/(T_(f))=(“Fusion enthalpy”)/(“Temperature”)`
`DeltaS_(f)=(2930 J “mol”^(-1))/(300 K)=9.77 JK^(-1) “mol”^(-1)`