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At 25°C, the standard enthalpy of formation of KCl(s) is –435.87 kJ/mol. When one mole of KCl(s) is formed by reacting potassium vapor and chlorine gas at 25°C, the standard enthalpy of reaction is –525.86 kJ/mol. Find ΔH° for the sublimation of potassium, K(s) → K(g), at 25°C
(A) –345.88 kJ/mol
(B) 45.00 kJ/mol
(C) 345.88 kJ/mol
(D) 89.99 kJ/mol
(E) –525.86 kJ/mol
At 25°C, the standard enthalpy of formation of KCl(s) is –435.87 kJ/mol. When one mole of KCl(s) is formed by reacting potassium vapor and chlorine gas at 25°C, the standard enthalpy of reaction is –525.86 kJ/mol. Find ΔH° for the sublimation of potassium, K(s) → K(g), at 25°C
(A) –345.88 kJ/mol
(B) 45.00 kJ/mol
(C) 345.88 kJ/mol
(D) 89.99 kJ/mol
(E) –525.86 kJ/mol
(D) 89.99 kJ/mol