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Parveen Ahluwalia
Asked: 2022-11-06T23:10:27+05:30 In:

Assume that the number of hole-electron pair in an intrinsic semiconductor is proportional to `e^(- Delta E//2KT)`. Here `Delta E` = energy gap and `k=8.62 xx 10^(-5) eV//”kelvin”`
The energy gap for silicon is `1.1 eV`. The ratio of electron hole pairs at`300 K` and `400 K` is :
A. `e^(-5.31)`
B. `e^(-5)`
C. `e`
D. `e^(2)`

Assume that the number of hole-electron pair in an intrinsic semiconductor is proportional to `e^(- Delta E//2KT)`. Here `Delta E` = energy gap and `k=8.62 xx 10^(-5) eV//”kelvin”`
The energy gap for silicon is `1.1 eV`. The ratio of electron hole pairs at`300 K` and `400 K` is :
A. `e^(-5.31)`
B. `e^(-5)`
C. `e`
D. `e^(2)`
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1 Answer

  1. Correct Answer – A
    ` (N_(1))/(N_(2))=(e^(-Delta E//2KT_(1)))/(e^(-Delta E//2KT_(2)))`
    `= e^((Delta E)/(2K)((1)/(T_(2))-(1)/(T_(1)))) =(1.1)/(e^(2xx8.62 xx10^(-5))) ((1)/(400)-(1)/(300))`.

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