An orange precipitate of group II is dissolve in cone HCI the solution when treated with excess of water turn milky due to formation of
A. Sn(OH)CI
B. `Sb(OH)CI_(2)`
C. SbOCI
D. `Sb(OH)_(2)Cl`
A. Sn(OH)CI
B. `Sb(OH)CI_(2)`
C. SbOCI
D. `Sb(OH)_(2)Cl`
Correct Answer – c
`Sb_(2)S_(3) + 6HCI rarr 2SbCI_(3) + 3H_(3)S`
`SbCI_(3) + H_(2)O rarr SbOCI + 2HCI`