An object of mass 0.2 kg executes simple harmonic oscillation along the x-axis with a frequency `(25)/pi`. At the position x = 0.04m, the object has kinetic amplitude of osciallation is (potential energy is zero mean position).
`x = 0.04 m, K.E. = 0.5 J and P.E. = 0.4 J`
`T.E. = (0.5 + 0.4) J = 0.9 J`
Now, `T.E. = (1)/(2)m omega^2 a^2 = (1)/(2) m xx 4 pi^2 v^2 a^2`
rArr `0.9 = (1)/(2) xx 0.1 xx 4 pi^2 xx (25)/(pi) xx (25)/(pi) xx a^2 rArr a = 0.06 m`.
Correct Answer – `A = 0.06 m`