An element crystallising in body centred cublic lattice has edge length of 500 pm. If the density is 4 g `cm^(-3)`, the atomic mass of the element `(“in g mol”^(-1))` is (consider `N_(A)=6xx10^(23))`
A. 100
B. 250
C. 125
D. 150
A. 100
B. 250
C. 125
D. 150
Correct Answer – D
`M=(rhoxxN_(A)xxa^(3)xx10^(-30))/Z`
`M=((4 g cm^(-3))xx(6xx10^(23)mol^(-1))xx(500)^(3)xx(10^(-30)cm^(3)))/2`
`=150 g ” mol”^(-1)`