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Raj Jacob
Asked: 2022-11-05T15:12:16+05:30 In:

An electric bulb is designed to draw `P_(0)` power at `V_(0)` voltage. If the voltage is `V`, it drawas power. Then
A. `P = ((V_0)/(V))P_(0)`
B. `P = ((V)/(V_0))P_(0)`
C. `P = ((V)/(V_0))^(2)P_(0)`
D. `P = ((V_0)/(V))^(2)P_(0)`

An electric bulb is designed to draw `P_(0)` power at `V_(0)` voltage. If the voltage is `V`, it drawas power. Then
A. `P = ((V_0)/(V))P_(0)`
B. `P = ((V)/(V_0))P_(0)`
C. `P = ((V)/(V_0))^(2)P_(0)`
D. `P = ((V_0)/(V))^(2)P_(0)`
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1 Answer

  1. Correct Answer – C
    `R_(B) = (V_0^2)/(P_0)`
    `P = (V^2)/(R_B) = ((V)/(V_0))^(2)P_(0)`.

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