An athelete takes 2.0 s to reach his maximum speed of 18.0 km/h. What is the magnitude of his average acceleration?
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Correct Answer – B
Initial velocity
u=0
(Since starts from rest)
FiN/Al velocity
v=18km/hr=5sec
(i.e. maximum velocity)
Time inteval
t=2 sec.
`:. Acceleration = a_(av)=((v-u))/2
=5/2= 2.5m/s^2`