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Ankita Sehgal
Asked: 2022-11-11T23:52:01+05:30 In:

An astronomical telescope has an angular magnification of magnitude 5 for distant object. The separation between the objective and the eyepiece is 36 cm and the final image is formed at infinity. The focal length `f_(0)` of the objective and the focal length `f_(0)` of the eyepiece are
A. `f_(o) = 45 cm and f_(e) = -9cm`
B. `f_(o) = -7.2 cm and f_(e) = 5 cm`
C. `f_(o) = 50 cm and f_(e) = 10 cm`
D. `f_(o) = 30 cm and f_(e) = 6 cm`

An astronomical telescope has an angular magnification of magnitude 5 for distant object. The separation between the objective and the eyepiece is 36 cm and the final image is formed at infinity. The focal length `f_(0)` of the objective and the focal length `f_(0)` of the eyepiece are
A. `f_(o) = 45 cm and f_(e) = -9cm`
B. `f_(o) = -7.2 cm and f_(e) = 5 cm`
C. `f_(o) = 50 cm and f_(e) = 10 cm`
D. `f_(o) = 30 cm and f_(e) = 6 cm`
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  1. Correct Answer – D
    In this case, `|m|=(f_(o))/(f_(e ))=5` …..(i)
    and length of telescope `= f_(o)+f_(e )=36` …..(ii)
    On solving Eqs. (i) and (ii), we get
    `f_(e )=6 cm, f_(o)=30 cm`

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Abhishek Halder
Asked: 2022-11-10T01:54:23+05:30 In:

An astronomical telescope has an angular magnification of magnitude 5 for distant object. The separation between the objective and the eyepiece is 36 cm and the final image is formed at infinity. The focal length `f_(0)` of the objective and the focal length `f_(0)` of the eyepiece are
A. `f_(o)=45 cm and f_(e)=-9cm`
B. `f_(o)=-7.2 cm and f_(e)=5cm`
C. `f_(o)=50 cm and f_(e)=10cm`
D.

An astronomical telescope has an angular magnification of magnitude 5 for distant object. The separation between the objective and the eyepiece is 36 cm and the final image is formed at infinity. The focal length `f_(0)` of the objective and the focal length `f_(0)` of the eyepiece are
A. `f_(o)=45 cm and f_(e)=-9cm`
B. `f_(o)=-7.2 cm and f_(e)=5cm`
C. `f_(o)=50 cm and f_(e)=10cm`
D.
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  1. Correct Answer – D
    (d) In this case, `abs(m)=f_(0)/(f_(e))=5`
    and the length of telescope = `f_(0)+f_(e)=36`
    On solving Eqs. (i) and (ii), we get
    `f_(e)=6 cm, f_(0)=30 cm`

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Bhairavi Bharat Brahmbhatt
Asked: 2022-10-29T15:04:31+05:30 In:

An astronomical telescope has an angular magnification of magnitude `5` for distant object. The separation between the objective and eyepiece is `36cm` and the final image is formed at infinity. Determine the focal length of objective and eyepiece.
A. `f_0 = 45 and f_e = -9 cm`
B. `f_0 = 50 cm and f_e = 10 cm`
C. `f_0 = 7.2 cm and f_e = 5 cm`
D. `f_0 = 30 cm and f_e = 6 cm`.

An astronomical telescope has an angular magnification of magnitude `5` for distant object. The separation between the objective and eyepiece is `36cm` and the final image is formed at infinity. Determine the focal length of objective and eyepiece.
A. `f_0 = 45 and f_e = -9 cm`
B. `f_0 = 50 cm and f_e = 10 cm`
C. `f_0 = 7.2 cm and f_e = 5 cm`
D. `f_0 = 30 cm and f_e = 6 cm`.
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1 Answer

  1. Correct Answer – D
    Here, Angular magnification of telescope
    `= (f_0)/(f_e) = 5`,
    `:. f_0 = 5 f_e` …(i)
    Now, `f_0 + f_e = 36 cm` ….(ii)
    On solving (i) and (ii), we get
    `5 f_e + f_e = 36 cm`
    `f_e = 6 cm, f_0 = 30 cm`.

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