An aqueous solution containing 288gm of a non-volatile compound having the stochiometric composition `”C”_(“X”)”H”_(“2X”)”O”_(“X”)` in 90gm water boils at `101.24^(@)”C”` at 1.00 atmospheric pressure. What is the molecular formula?
`”K”_(“b”)(“H”_(2)”O”)=0.512″ K mol”^(-1) “kg”” T”_(“b”)(“H”_(2)”O”)=100^(@)”C”`
`”K”_(“b”)(“H”_(2)”O”)=0.512″ K mol”^(-1) “kg”” T”_(“b”)(“H”_(2)”O”)=100^(@)”C”`
Elevation in B.P `=101.24-100=1.24^(@)”C”`
`Delta “T”_(“b”)=”K”_(“b”)xx”i”xx”molality” implies1.24=0.512xx288/”m”xx1000/90 (therefore”i”=1)`
`therefore “m”=1321.2″gm mol”^(-1)`
molar mass of `”C”_(“X”)”H”_(“2X”)”O”_(“X”)=12″x”+1xx2″x”+16″x”=30″x”`
`therefore “x”=44`
Hence the molecular formula is `=”C”_(“44”)”H”_(“88”)”O”_(“44”)`