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Chinmay Kar
Chinmay Kar
Asked: 3 years ago2022-11-10T13:22:44+05:30 2022-11-10T13:22:44+05:30In: Mensuration

ABCD is a trapezium in which AB ∥ DC, M is mid-point of AD and N is mid-point of BC. If the length of AB is 14 cm and the length of MN is 17 cm, then find the length of CD.
1. 20 cm
2. 10 cm
3. 15 cm
4. 25 cm

ABCD is a trapezium in which AB ∥ DC, M is mid-point of AD and N is mid-point of BC. If the length of AB is 14 cm and the length of MN is 17 cm, then find the length of CD.
1. 20 cm
2. 10 cm
3. 15 cm
4. 25 cm
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  1. 96162
    2022-10-29T18:11:18+05:30Added an answer about 3 years ago

    Correct Answer – Option 1 : 20 cm

    Given:

    ABCD is a trapezium, AB ∥ DC

    M is mid-point of AD

    N is mid-point of BC

    AB = 14 cm

    MN = 17 cm

    Formula Used:

    MN = 1/2 × (AB + CD)

    In a trapezium AB ∥ DC

    And M and N are mid-points of AD and BC respectively.

    Calculation:

    MN = 1/2 × (AB + CD)

    ⇒ 17 = 1/2 × (14 + CD)

    ⇒ 34 = 14 + CD

    ⇒ CD = 34 – 14

    ⇒ CD = 20 cm

    ∴ The length of CD is 20 cm.

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Gowri Bal
Gowri Bal
Asked: 3 years ago2022-11-09T20:45:51+05:30 2022-11-09T20:45:51+05:30In: Mensuration

ABCD is a trapezium in which AB ∥ DC, M is mid-point of AD and N is mid-point of BC. If the length of AB is 71.5 cm and the length of CD is 52 cm, then find the length of MN.
1. 59.50 cm
2. 61.75 cm
3. 63.50 cm
4. 55.25 cm

ABCD is a trapezium in which AB ∥ DC, M is mid-point of AD and N is mid-point of BC. If the length of AB is 71.5 cm and the length of CD is 52 cm, then find the length of MN.
1. 59.50 cm
2. 61.75 cm
3. 63.50 cm
4. 55.25 cm
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  1. 34bef
    2022-10-31T04:10:17+05:30Added an answer about 3 years ago

    Correct Answer – Option 2 : 61.75 cm

    Given:

    ABCD is a trapezium, AB ∥ DC

    M is mid-point of AD

    N is mid-point of BC

    AB = 71.5 cm

    CD = 52 cm

    Formula Used:

    MN = 1/2 × (AB + CD)

    In a trapezium AB ∥ DC

    And M and N are mid-points of AD and BC respectively.

    Calculation:

    MN = 1/2 × (AB + CD)

    ⇒ MN = 1/2 × (71.5 + 52)

    ⇒ MN = 1/2 × 123.5

    ⇒ MN = 61.75 cm

    ∴ The length of MN is 61.75 cm.

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Preet Raj Warrior
Preet Raj Warrior
Asked: 3 years ago2022-11-04T06:38:48+05:30 2022-11-04T06:38:48+05:30In: Mensuration

ABCD is a trapezium in which AB ∥ DC, M is mid-point of AD and N is mid-point of BC. If the length of AB is 40.25 cm and the length of MN is 49 cm, then find the length of CD.
1. 52.25 cm
2. 48.75 cm
3. 57.75 cm
4. 59.50 cm

ABCD is a trapezium in which AB ∥ DC, M is mid-point of AD and N is mid-point of BC. If the length of AB is 40.25 cm and the length of MN is 49 cm, then find the length of CD.
1. 52.25 cm
2. 48.75 cm
3. 57.75 cm
4. 59.50 cm
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  1. 809b8
    2022-11-09T15:34:22+05:30Added an answer about 3 years ago

    Correct Answer – Option 3 : 57.75 cm

    Given:

    ABCD is a trapezium, AB ∥ DC

    M is mid-point of AD

    N is mid-point of BC

    AB = 40.25 cm

    MN = 49 cm

    Formula Used:

    MN = 1/2 × (AB + CD)

    In a trapezium AB ∥ DC

    And M and N are mid-points of AD and BC respectively.

    Calculation:

    MN = 1/2 × (AB + CD)

    ⇒ 49 = 1/2 × (40.25 + CD)

    ⇒ 98 = 40.25 + CD

    ⇒ CD = 98 – 40.25

    ⇒ CD = 57.75 cm

    ∴ The length of CD is 57.75 cm.

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Zahir Chandra Babu
Zahir Chandra Babu
Asked: 3 years ago2022-11-01T16:38:48+05:30 2022-11-01T16:38:48+05:30In: Mensuration

ABCD is a trapezium in which AB ∥ DC, M is mid-point of AD and N is mid-point of BC. If the length of CD is 19 cm and the length of MN is 15.5 cm, then find the length of AB.
1. 20 cm
2. 12 cm
3. 15 cm
4. 18 cm

ABCD is a trapezium in which AB ∥ DC, M is mid-point of AD and N is mid-point of BC. If the length of CD is 19 cm and the length of MN is 15.5 cm, then find the length of AB.
1. 20 cm
2. 12 cm
3. 15 cm
4. 18 cm
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  1. eb9bb
    2022-10-30T02:43:42+05:30Added an answer about 3 years ago

    Correct Answer – Option 2 : 12 cm

    Given:

    ABCD is a trapezium, AB ∥ DC

    M is mid-point of AD

    N is mid-point of BC

    CD = 19 cm

    MN = 15.5 cm

    Formula Used:

    MN = 1/2 × (AB + CD)

    In a trapezium AB ∥ DC

    And M and N are mid-points of AD and BC respectively.

    Calculation:

    MN = 1/2 × (AB + CD)

    ⇒ 15.5 = 1/2 × (AB + 19)

    ⇒ 31 = AB + 19

    ⇒ AB = 31 – 19

    ⇒ AB = 12 cm

    ∴ The length of AB is 12 cm.

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Bagwati Nakul Sandhu
Bagwati Nakul Sandhu
Asked: 3 years ago2022-10-31T18:37:42+05:30 2022-10-31T18:37:42+05:30In: Mensuration

ABCD is a trapezium in which AB ∥ DC, M is mid-point of AD and N is mid-point of BC. If the length of AB is 18 cm and the length of CD is 12 cm, then find the length of MN.
1. 20 cm
2. 12 cm
3. 15 cm
4. 18 cm

ABCD is a trapezium in which AB ∥ DC, M is mid-point of AD and N is mid-point of BC. If the length of AB is 18 cm and the length of CD is 12 cm, then find the length of MN.
1. 20 cm
2. 12 cm
3. 15 cm
4. 18 cm
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  1. 192ed
    2022-11-04T12:24:26+05:30Added an answer about 3 years ago

    Correct Answer – Option 3 : 15 cm

    Given:

    ABCD is a trapezium, AB ∥ DC

    M is mid-point of AD

    N is mid-point of BC

    AB = 18 cm

    CD = 12 cm

    Formula Used:

    MN = 1/2 × (AB + CD)

    In a trapezium AB ∥ DC

    And M and N are mid-points of AD and BC respectively.

    Calculation:

    MN = 1/2 × (AB + CD)

    ⇒ MN = 1/2 × (18 + 12)

    ⇒ MN = 1/2 × 30

    ⇒ MN = 15

    ∴ The length of MN is 15 cm.

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