A two digit no. Is 4 times the sum of its digits.and twice the digits. Find the no.
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Let the ten\’s place digit be y and unit\’s place be x.Therefore, number is 10y + x.According to given condition,10y + x = 4(x + y) and 10y + x = 2xy{tex}\\Rightarrow{/tex}\xa0x = 2y and 10y + x = 2xyPutting x = 2y in 10y + x = 2xy10y + 2y = 2.2y.y12y = 4y2\xa04y2\xa0- 12y = 0\xa0{tex}\\Rightarrow{/tex}\xa04y(y – 3) = 0{tex}\\Rightarrow{/tex}\xa0y – 3 = 0 or y = 3Hence, the ten\’s place digit is 3 and units digit is 6 (2y = x)Hence the required number is 36.