A TV was sold at a price of 70% higher than it was bought. A fridge was sold at 40% of its price. The price of fridge was Rs. 9000 more than the price of TV. Both the items were sold at a total of Rs. 28800. Find the selling price of the fridge.
1. Rs. 10000
2. Rs. 7800
3. Rs. 21000
4. Rs. 8400
1. Rs. 10000
2. Rs. 7800
3. Rs. 21000
4. Rs. 8400
Correct Answer – Option 4 : Rs. 8400
Given:
The price of fridge = The price of TV + Rs. 9000
SP of TV = 70% higher than CP of TV
SP of fridge = 40% of CP of fridge
Sum of the SP of both the items = Rs. 28800
Calculation:
Let the CP of TV and fridge be x and (x + 9000) respectively
SP of fridge = 40% of CP of fridge
⇒ SP of fridge = 0.4(x + 9000)
SP of TV = 70% higher than CP of TV
⇒ SP of TV = CP of TV + 70% of CP
⇒ SP of TV = 1.7x
The sum of the SP = 28800
⇒ 1.7x + 0.4(x + 9000) = 28800
⇒ 2.1x = 28800 – 3600
⇒ 2.1x = 25200
⇒ x = 12000
SP of fridge = 0.4(x + 9000)
⇒ 0.4(12000 + 9000)
⇒ 8400
∴ The selling price of fridge is Rs. 8400.