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Ramesh Lal Samra
Asked: 2022-10-29T01:46:38+05:30 In:

A trailer with loaded weight`F_(g)` is being pulled by a vehicle with a force `P`, as in figure. The trailer is loaded such that its centre of mass is located as shown. Neglect the force of rolling friction and let a represent the `x` component of the acceleration of the trailer. (a) Find the vertical component of `P` in terms of the given parameters. (b) If a` =2.00 ms^(-2)` and `h = 1.50 m`, what must be the value of `d` in order that `P = 0` (no vertical load on the vehicle)?
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A trailer with loaded weight`F_(g)` is being pulled by a vehicle with a force `P`, as in figure. The trailer is loaded such that its centre of mass is located as shown. Neglect the force of rolling friction and let a represent the `x` component of the acceleration of the trailer. (a) Find the vertical component of `P` in terms of the given parameters. (b) If a` =2.00 ms^(-2)` and `h = 1.50 m`, what must be the value of `d` in order that `P = 0` (no vertical load on the vehicle)?
image
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  1. a. If the acceleration is a we have `P_(x)=ma` and `P_(y)+n-F_(g)=0`
    Taking the origin at the centre of gravity, the torque equation gives
    `P_(y)(L-d)+P_(x)h-nd=0`
    Solving these equations, we find `P_(Y)=(F_(g))/L(d-(ah)/g)`
    b. If `P_(y)=0,` then
    `d=(ah)/g=((2.00ms^(-2))(1.50m))/(10ms^(-2))=0.30m`

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