A tower ab is is 20 m high and be. It\’s shadow on the ground is20m long find the sun s. Altitude
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Let the tower AB = 20m and shadow BC {tex}= 20\\sqrt3 m{/tex}{tex}\\angle A C B = \\theta{/tex}{tex}\\tan \\theta = \\frac { A B } { B C }{/tex}{tex}\\tan \\theta = \\frac { 20 } { 20 \\sqrt { 3 } } = \\frac { 1 } { \\sqrt { 3 } } = \\tan 30 ^ { \\circ }{/tex}\xa0{tex}\\Rightarrow \\quad \\theta = 30 ^ { \\circ }{/tex}Therefore ,the Sun’s altitude is 30°.