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Rajendra Mehrotra
Asked: 2022-11-10T20:59:53+05:30 In:

A thin wire of mass m and length l is bent in the form of a ring . Moment of inertia of that ring about an axis passing through its centre and perpendicular to its through its centre and perpendicular to its plane is
A. `ml^(2)//4pi`
B. `ml^(2)//2pi`
C. `ml^(2)//4pi^(2)`
D. `ml^(2)//2pi^(2)`

A thin wire of mass m and length l is bent in the form of a ring . Moment of inertia of that ring about an axis passing through its centre and perpendicular to its through its centre and perpendicular to its plane is
A. `ml^(2)//4pi`
B. `ml^(2)//2pi`
C. `ml^(2)//4pi^(2)`
D. `ml^(2)//2pi^(2)`
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1 Answer

  1. Correct Answer – C
    `2pi r = l ” ” therefore r = (l)/(2 pi)`
    `I = mr^(2)`
    `= (ml^(2))/(4pi^(2))`. `I = mr^(2)`
    `= (ml^(2))/(4pi^(2))`.

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