A student takes a quiz consisting of 5 multiple choice questions. Each question has 4 possible answers. If a student is guessing the answer at random and answer to different are independent, then the probability of atleast one correct answer is
1. 0.237
2. 0.00076
3. 0.7627
4. 1
1. 0.237
2. 0.00076
3. 0.7627
4. 1
Correct Answer – Option 3 : 0.7627
Concept:
If there can be only 2 cases of true and false, then:
Probability of r true cases out of n (≥ r) P(x = r) = nCr prq(n-r)
where p is the probability of case being true and q is probability of case being false
Note: p and q are ≤ 1
Calculation:
The probability of correct answer p = \(\rm 1\over 4\) = 0.25
The probability of wrong answer q = \(\rm 3\over 4\) = 0.75
Total questions n = 5
Probability of atleast one correct answer (x ≥ 1):
P(x ≥ 1) = 1 – P(x = 0)
⇒ P(x ≥ 1) = 1 – 5C0 p0q5
⇒ P(x ≥ 1) = 1 – (0.75)5
⇒ P(x ≥ 1) = 1 – 0.2373
⇒ P(x ≥ 1) \(\boldsymbol{\rm \approx}\) 0.7627