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Naresh Chopra
Asked: 2022-11-09T06:20:25+05:30 In:

A stretched wire of lenth 110 cm is divided into three
segments whose frequencies are in ratio `1 : 2 : 3.` Their
length must be
A. 20 cm, 30 cm, 60 cm,
B. 60 cm, 30 cm, 20 cm
C. 60 cm, 20 cm, 30 cm,
D. 30 cm, 60 cm, 20 cm

A stretched wire of lenth 110 cm is divided into three
segments whose frequencies are in ratio `1 : 2 : 3.` Their
length must be
A. 20 cm, 30 cm, 60 cm,
B. 60 cm, 30 cm, 20 cm
C. 60 cm, 20 cm, 30 cm,
D. 30 cm, 60 cm, 20 cm
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  1. Correct Answer – b
    Given `l_(1)+l_(2)+l_(3)=110` cm
    and `n_(1)l_(1)=n_(2)l_(2)=n_(3)l_(3)` (`because` T and d are same)
    `n_(1):n_(2):n_(3)::1 : 2: 3`
    `because n_(1)/n_(2)=1/2=l_(2)/l_(1)rArr l_(2)=l_(1)/2`
    and `because n_(1)/n_(3)=1/3=l_(3)/l_(1)rArr l_(3)=l_(1)/3`
    `therefore l_(1) +l_(1)/2+l_(1)/3=110`
    `rArr l_(1) = 60 ` cm
    So, ` l_(1) = 60 ` cm, `l_(2) = 30` cm, ` l_(3) = 20` cm

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