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Ajeet Deshpande
Asked: 2022-11-09T14:13:30+05:30 In:

A steel rod of length `1 m` is heated from `25^@ “to” 75^@ C` keeping its length constant. The longitudinal strain developed in the rod is ( Given, coefficient of linear expansion of steel = `12 xx 10^-6//^@ C`).
A. `6 xx 10^-4`
B. `-6 xx 10^-5`
C. `-6 xx 10^-4`
D. zero

A steel rod of length `1 m` is heated from `25^@ “to” 75^@ C` keeping its length constant. The longitudinal strain developed in the rod is ( Given, coefficient of linear expansion of steel = `12 xx 10^-6//^@ C`).
A. `6 xx 10^-4`
B. `-6 xx 10^-5`
C. `-6 xx 10^-4`
D. zero
Parabola
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  1. Correct Answer – C
    It means rod is compressed from its natural length by `Delta l`.
    `:.` Strain `= – (Delta l)/l = -(l Delta alpha Delta theta)/l`
    `= (- alpha d theta) = – (12 xx 10^-6)(50)`
    = `- 6 xx 10^-4`.

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Sukriti Ganesh Nazareth
Asked: 2022-11-08T03:21:37+05:30 In:

A steel rod of length `1 m` is heated from `25^@ “to” 75^@ C` keeping its length constant. The longitudinal strain developed in the rod is ( Given, coefficient of linear expansion of steel = `12 xx 10^-6//^@ C`).
A. `-6 xx 10^(-6)`
B. `-6 xx 10^(-5)`
C. `-6 xx 10^(-4)`
D. zero

A steel rod of length `1 m` is heated from `25^@ “to” 75^@ C` keeping its length constant. The longitudinal strain developed in the rod is ( Given, coefficient of linear expansion of steel = `12 xx 10^-6//^@ C`).
A. `-6 xx 10^(-6)`
B. `-6 xx 10^(-5)`
C. `-6 xx 10^(-4)`
D. zero
Parabola
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1 Answer

  1. Correct Answer – C
    Strain developed:
    `epsilon = alpha Delta T = (12 xx 10^(-6))(50)=6 xx 10^(-4)`
    Strain will be negative, as the rod is in a compressed state.

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Payal Sami
Asked: 2022-10-29T16:53:38+05:30 In:

A steel rod of length `1 m` is heated from `25^@ “to” 75^@ C` keeping its length constant. The longitudinal strain developed in the rod is ( Given, coefficient of linear expansion of steel = `12 xx 10^-6//^@ C`).
A. `6 xx 10^(-6)`
B. `-6 xx 10^(-5)`
C. `-6 xx 10^(-4)`
D. zero

A steel rod of length `1 m` is heated from `25^@ “to” 75^@ C` keeping its length constant. The longitudinal strain developed in the rod is ( Given, coefficient of linear expansion of steel = `12 xx 10^-6//^@ C`).
A. `6 xx 10^(-6)`
B. `-6 xx 10^(-5)`
C. `-6 xx 10^(-4)`
D. zero
Parabola
Leave an answer

Leave an answer

Browse

1 Answer

  1. Correct Answer – C
    Strain developed:
    ` epsilon= alpha Delta T = (12 xx 10^(-6))(50)=6xx10^(-4)`
    Strain will be negative, as the rod is in a compressed state.

    • 0