Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
Correct Answer – A::C::D
If intensity at a point is `I`. Then energy density at that point is `E=(I)/(v)`, where `v` is wave propagation velocity.
It means that `EpropI`. Hence, the graph between `E` and `I` will be a straight line passing through the origin. Therefore, (a) is correct and (b) is wrong. Intensity is given by
`I=2pi^2n^2a^2rhov`
Hence, `E=2pi^2n^2a^2rho`
It means that `Epropn^2`
Hence, the graph between `E` and `n` will be a parabola passing through origin, having increasing slope and symmetric about E-axis, Hence, option (d) is correct.
Particle maximum velocity is
`u_0=aomega=2pina`
`impliespina=(u_0)/(2)`
Hence, `E=(1)/(2)rhou_0^2`
It means that graph between `E` and `u_0` will be a parabola, have increasing slope and will be symmetric about E-axis. Hence, option (c ) is also correct.
Correct Answer – A::C::D
If intensity at a point is `I`. Then energy density at that point is `E=(I)/(v)`, where `v` is wave propagation velocity.
It means that `EpropI`. Hence, the graph between `E` and `I` will be a straight line passing through the origin. Therefore, (a) is correct and (b) is wrong. Intensity is given by
`I=2pi^2n^2a^2rhov`
Hence, `E=2pi^2n^2a^2rho`
It means that `Epropn^2`
Hence, the graph between `E` and `n` will be a parabola passing through origin, having increasing slope and symmetric about E-axis, Hence, option (d) is correct.
Particle maximum velocity is
`u_0=aomega=2pina`
`impliespina=(u_0)/(2)`
Hence, `E=(1)/(2)rhou_0^2`
It means that graph between `E` and `u_0` will be a parabola, have increasing slope and will be symmetric about E-axis. Hence, option (c ) is also correct.