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Alka Aayushman Sheth
Asked: 2022-10-29T01:29:56+05:30 In:

A solution of HCI is prepared by dissolving 5.5 g HCI in 200 g ehanol. The density of the solution is 0.79 g `mL^(-1)` Molarity of solution is :
A. 0.58 M
B. 0.16 M
C. 0.92 M
D. 1.2 M

A solution of HCI is prepared by dissolving 5.5 g HCI in 200 g ehanol. The density of the solution is 0.79 g `mL^(-1)` Molarity of solution is :
A. 0.58 M
B. 0.16 M
C. 0.92 M
D. 1.2 M
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1 Answer

  1. Correct Answer – a
    `”Molarity (M)”=(“Mass of HCI//Molar mass”)/(“Volame of solution in litrese”)`
    Mass of HCI solution = 200+5.5=205.5 g
    Density of solution = 0.79 g `mL^(-1)`
    `”Volume of solution”=((205.5g))/((0.79gmL^(-1)))`
    =260L
    `”Molarity”=((5.5g)//(36.5g mol^(-1)))/(0.260L)`
    =0.58 `mL^(-1)=0.58 M`

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