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Gunjan Prakash
Asked: 2022-11-04T18:47:37+05:30 In:

A solid has a structure in which `X` atoms are located at cubic corners of unit cell, `O` atom are at the edge centres and `Y` atoms at cube centre.
Then the formula of compound is `X_(a)Y_(b)O_(c)`
If two atoms of `O` missing from any of two edge centres per unit cell, then the molecular formula is `X_(a)Y_(b)O_(z)`. Then, find the value of `(x + y + z) – (a + b+ c)`.

A solid has a structure in which `X` atoms are located at cubic corners of unit cell, `O` atom are at the edge centres and `Y` atoms at cube centre.
Then the formula of compound is `X_(a)Y_(b)O_(c)`
If two atoms of `O` missing from any of two edge centres per unit cell, then the molecular formula is `X_(a)Y_(b)O_(z)`. Then, find the value of `(x + y + z) – (a + b+ c)`.
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  1. Correct Answer – 4
    a. Number of X atoms `=8xx(1)/(8)=1`/unit cell.
    Number of Y atoms=1/unit cell. Number of O atoms `=12xx(1)/(4)=3` /unit cell
    Formula is : `XYO_(3)rArrX_(a)Y_(b)O_(c)`
    b. Number of O atoms missing from two edge centers per unit cell `=2xx(1)/(4)=(1)/(2)` /unit cell
    Number of O atoms left `=3-(1)/(2)=2.5`/unit cell
    Formula is `XYO_(2.5)rArrX_(2)Y_(2)O_(5)rArrX_(x)Y_(y)O_(z)`
    `therefore` Total value of
    `(x+y+z)-(a+b+c)=(2+2+5)-(1+1+3)=4`

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