A solid has a bcc structure. If the distance of closest approach between the two atoms is 1.73 Å. The edge length of the cell is …….
(A) 200 pm
(B) \(\cfrac{\sqrt{3}}{\sqrt{2}}\) pm
(C) 142.2 pm
(D) \(\sqrt{2}\) pm
Correct Answer – A
`r_(“atom”) = (sqrt3)/(4)` a , Also closest approach in bcc lattice is `1/2` of body diagonal , i.e. `(sqrt3)/(2) a = 1.73 Å`
or `a=(1.73xx2)/(sqrt3) = 1.966Å = 199.6` pm
Correct answer is: (A) 200 pm