A solid AB has rock salt structure. If the edge length is 520 pm and radius of A+ is 80 pm, the radius of anion B– would be……….
(A) 440 pm
(B) 220 pm
(C) 360 pm
(D) 180 pm
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Correct answer is: (D) 180 pm
2r+ + 2r– = 520
\(\therefore\) \(r^++r^-=\cfrac{520}{2}\)=r–=260 – 80 = 180 pm.