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Indrani Dodiya
Asked: 2022-11-11T22:09:18+05:30 In:

A small block of mass `1` kg is a circular are of ratius `40` m . The block sides along the track without topping and a frictionnal force acts on it in the direction opposite in the instrmens velocity . The work done in evercoming the friction up to the point `Q` as shown is the figure below is `150 J`
(Take the acceleration due to gravity `g = 10 ms^(-2))`
image
The magnitude of the normal reaction that acts on the block at the point `Q` is
A. (a) `7.5N`
B. (b) `8.6N`
C. (c) `11.5N`
D. (d) `22.5N`

A small block of mass `1` kg is a circular are of ratius `40` m . The block sides along the track without topping and a frictionnal force acts on it in the direction opposite in the instrmens velocity . The work done in evercoming the friction up to the point `Q` as shown is the figure below is `150 J`
(Take the acceleration due to gravity `g = 10 ms^(-2))`
image
The magnitude of the normal reaction that acts on the block at the point `Q` is
A. (a) `7.5N`
B. (b) `8.6N`
C. (c) `11.5N`
D. (d) `22.5N`
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1 Answer

  1. Correct Answer – A
    `N-mg cos 60^@=(mv^2)/(R)`
    `N=5+5/2=7.5N c`

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