A single conservative `f_((x))` acts on a `m = 1 kg` particle moving along the x-axis. The potential energy `U_((x))` is given by :
`U_((x)) = 20 + (x – 2)^(2)`
where x is in metres. At `x = 5 m`, a particle has kintetic energy of 20 J
The least value of x (position of particle is ) will be:
A. zero
B. `-2`
C. `- sqrt(29) + 2`
D. `sqrt(29) + 2`

A single conservative `f_((x))` acts on a `m = 1 kg` particle moving along the x-axis. The potential energy `U_((x))` is given by :
`U_((x)) = 20 + (x – 2)^(2)`
where x is in metres. At `x = 5 m`, a particle has kintetic energy of 20 J
The maximum value of potential energy is:
A. zero
B. 20 J
C. 29 J
D. 49 J

A single conservative `f_((x))` acts on a `m = 1 kg` particle moving along the x-axis. The potential energy `U_((x))` is given by :
`U_((x)) = 20 + (x – 2)^(2)`
where x is in metres. At `x = 5 m`, a particle has kintetic energy of 20 J
The maximum speed of the particle is:
A. `1 m//s`
B. `29 m//s`
C. `sqrt(29) m//s`
D. `sqrt(58) m//s`

A single conservative `f_((x))` acts on a `m = 1 kg` particle moving along the x-axis. The potential energy `U_((x))` is given by :
`U_((x)) = 20 + (x – 2)^(2)`
where x is in metres. At `x = 5 m`, a particle has kintetic energy of 20 J
The largest value of x will be:
A. zero
B. `-2`
C. `- sqrt(29) + 2`
D. `sqrt(29) + 2`