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Samir Venkat Sarin
Asked: 2022-11-09T15:19:11+05:30 In:

A rope thrown over a pulley has a ladder with a man of mass `m` on one of its ends and a counter balancing mass `M` on its other end. The man climbs with a velocity `v_r` relative to ladder. Ignoring the masses of the pulley and the rope as well as the friction on the pulley axis, the velocity of the centre of mass of this system is:
A. `m/M v_(r)`
B. `m/(2M)v_(r)`
C. `M/m v_(r)`
D. `(2M)/m v_(r)`

A rope thrown over a pulley has a ladder with a man of mass `m` on one of its ends and a counter balancing mass `M` on its other end. The man climbs with a velocity `v_r` relative to ladder. Ignoring the masses of the pulley and the rope as well as the friction on the pulley axis, the velocity of the centre of mass of this system is:
A. `m/M v_(r)`
B. `m/(2M)v_(r)`
C. `M/m v_(r)`
D. `(2M)/m v_(r)`
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  1. Correct Answer – B
    The masses of load, ladder and man are `M,M-m` and `m` repectively. Their velocities are `v`(upward),`-v` and `v_(r)-v` respectively
    ` :. V_(cm)=(sum m_(i)v_(i))/(summ_(i))`
    `=(M(v)+(M-m)(-v)+m(v_(r)-v))/(2M)=m/(2M)v_(r)`

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