A projectile is projected with kinetic energy K, it has the maximum possible horizontal range, then its kinetic energy at the highest point will be
(a) 0.25 K
(b) 0.5 K
(c) 0.75 K
(d) K.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
A projectile is projected with kinetic energy K, it has the maximum possible horizontal range, then its kinetic energy at the highest point will be
(a) 0.25 K
(b) 0.5 K
(c) 0.75 K
(d) K.
A projectile is projected with kinetic energy K, it has the maximum possible horizontal range, then its kinetic energy at the highest point will be
(a) 0.25 K
(b) 0.5 K
(c) 0.75 K
(d) K.
Answer is (b) 0.5 K
Since range is maximum therefore θ = 45°, hence vx = ν cos45° = ν/√2.
At the highest point the net velocity of the projectile is νx.