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Taahid Som
Asked: 2022-11-10T02:03:56+05:30 In:

A person adds `1*71` gram of sugar `(C_(12)H_(22)O_(11))` in order to sweeten his tea. The number of carbon atoms added are (mol. mass of sugar – 342)
A. `3*6xx10^(22)`
B. `7*2xx10^(21)`
C. `0*05`
D. `6*6xx10^(22)`

A person adds `1*71` gram of sugar `(C_(12)H_(22)O_(11))` in order to sweeten his tea. The number of carbon atoms added are (mol. mass of sugar – 342)
A. `3*6xx10^(22)`
B. `7*2xx10^(21)`
C. `0*05`
D. `6*6xx10^(22)`
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  1. Correct Answer – A
    Moles of sugar added `= (1*71)/(342) = 5xx10^(-3)`
    Carbon atoms added
    `=12xx5xx10^(-3)xx6*02xx10^(23)`
    `= 3.61xx10^(22)`

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