A person adds 1.71 g of sugar `(C_(12)H_(22)O_(11))` in order to sweeten his tea. The number of carbon atoms added are (molecular mass of sugar = 342)
A. `3.6 xx 10^(22)`
B. `7.2 xx 10^(21)`
C. 0.05
D. `6.6 xx 10^(22)`
A. `3.6 xx 10^(22)`
B. `7.2 xx 10^(21)`
C. 0.05
D. `6.6 xx 10^(22)`
Number of moles of sugar `=(1.71)/(342)=0.005`
`because` 1 mole sugar contains
`=12xx6.02xx10^(23)`
`therefore 0.005` mole of sugar will contain
`=12xx0.005xx6.02xx10^(23)`
`=0.36xx10^(23)=3.6xx10^(22)` C-atoms