A pendulum of length 1m is released from theta =60 degree . The rate of change of speed of the bob at theta = 30 degree is
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We know that Rate change of speed, dv/dt= tangential acceleration =tangential force/mass
When θ=30∘, tangential force is mgsinθ
Therefore F=mgsin30
ma=mgsin30
a=mgsin30/m
=10sin30
=10×1/2
=5m/s2
So, The rate of change of speed of the bob at theta = 30 degree is 5m/s2