A parallel-plate capacitor has plates of area 10 cm2 separated by a distance of 1 mm. It is filled with the dielectric mica and connected to a battery of emf 6 volts. Find the leakage current through the capacitor. Resistivity of mica = 1 × 1013 Ω-m
1. 10 × 10-13 A
2. 1 × 10-13 A
3. 6 × 10-13 A
4. 3 × 10-13 A
1. 10 × 10-13 A
2. 1 × 10-13 A
3. 6 × 10-13 A
4. 3 × 10-13 A
Correct Answer – Option 3 : 6 × 10-13 A
The resistance of the mica between the two faces is
\(\rho \frac{l}{A} = \frac{{\left( {1 \times {{10}^{13}}} \right) \times {{10}^{ – 3}}}}{{10.0 \times {{10}^{ – 4}}}}\)
= 1 × 1013 Ω.
The leakage current \(= \frac{{6\;V}}{{1 \times {{10}^{13}}\;{\rm{\Omega }}}} = 6 \times {10^{ – 13}}A\)