A nut is placed in a nut cracker at 5 cm from the fixed end. If the force experienced by the nut is 100 N when a force of 20 N is applied at the free end of the nut cracker, find the length of the nut cracker.
A. 5
B. 25
C. 15
D. 20
A. 5
B. 25
C. 15
D. 20
Correct Answer – B
Mechanical advantage `=(“Load”)/(“Effort”)=(“Effort arm”)/(“Load arm”)`
Therefore, `(100)/(20)=(“Effort arm”)/(5)`
`implies` Effort arm =25 cm
Hence, the correct options is (b).