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Divya Datta
Asked: 2022-11-11T11:34:00+05:30 In:

A man of `50 kg` mass is standing in a gravity free space at a height of `10m` above the floor. He throws a stone of `0.5 kg` mass downwards with a speed `2m//s`. When the stone reaches the floor, the distance of the man above the floor will be
A. `9.9 m`
B. `10.1 m`
C. `1.0 m`
D. `20 m`

A man of `50 kg` mass is standing in a gravity free space at a height of `10m` above the floor. He throws a stone of `0.5 kg` mass downwards with a speed `2m//s`. When the stone reaches the floor, the distance of the man above the floor will be
A. `9.9 m`
B. `10.1 m`
C. `1.0 m`
D. `20 m`
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1 Answer

  1. Correct Answer – B
    Here, `m_(1)=50 kg, m_(2)=0.5kg`
    `u_(1)=?,u_(2)=2m//s`
    By momentum conservation,
    `m_(1)u_(1)+m_(2)u_(2)=0`
    `=u_(1)=(-m_(2)u_(2))/(m_(1))=(-0.5xx2)/(50)=(1)/(50)m//s`
    Negative sign is for upward motion of man. In gravity free space, time taken by stone to reach the floor, `t=(s)/(m_(1))=(10)/(2)=5s`
    Upward distance moved by the man `=u_(1)xxt`
    `=(1)/(50)xx5=0.1m.`
    `:.` Distance of man above the floor
    `=(10+0.1)m=10.1m`

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