A man `M_(1)` of mass `80 kg` runs up a statircase in `15 s`. Another man `M_(2)` also of mass `80 kg` runs up the same staricase in `20 s`. The ratio of the power devlopment by then will be:
A. 1
B. `(4)/(3)`
C. `(16)/(9)`
D. none of these
A. 1
B. `(4)/(3)`
C. `(16)/(9)`
D. none of these
Correct Answer – B
Power `P=` Work time
Work done by the will be same . Hence
`(P_(1))/(P_(2)) = (t_(2))/(t_(1)) = (20)/(15) = (4)/(3)` .